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   <ui>gb-2007-8-4-r54</ui>
   <ji>GBJ</ji>
   <fm>
      <dochead>Method</dochead>
      <bibl>
         <title>
            <p>Statistical tools for synthesizing lists of differentially expressed features in related experiments</p>
         </title>
         <aug>
            <au id="A1" ca="yes">
               <snm>Blangiardo</snm>
               <fnm>Marta</fnm>
               <insr iid="I1"/>
               <email>m.blangiardo@imperial.ac.uk</email>
            </au>
            <au id="A2">
               <snm>Richardson</snm>
               <fnm>Sylvia</fnm>
               <insr iid="I1"/>
               <email>sylvia.richardson@imperial.ac.uk</email>
            </au>
         </aug>
         <insg>
            <ins id="I1">
               <p>Centre for Biostatistics, Imperial College, St Mary's Campus, Norfolk Place, London W2 1PG, UK</p>
            </ins>
         </insg>
         <source>Genome Biology</source>
         <issn>1465-6906</issn>
         <pubdate>2007</pubdate>
         <volume>8</volume>
         <issue>4</issue>
         <fpage>R54</fpage>
         <url>http://genomebiology.com/2007/8/4/R54</url>
         <xrefbib>
            <pubidlist>
               <pubid idtype="pmpid">17428330</pubid>
               <pubid idtype="doi">10.1186/gb-2007-8-4-r54</pubid>
            </pubidlist>
         </xrefbib>
      </bibl>
      <history>
         <rec>
            <date>
               <day>7</day>
               <month>7</month>
               <year>2006</year>
            </date>
         </rec>
         <revrec>
            <date>
               <day>13</day>
               <month>11</month>
               <year>2006</year>
            </date>
         </revrec>
         <acc>
            <date>
               <day>11</day>
               <month>4</month>
               <year>2007</year>
            </date>
         </acc>
         <pub>
            <date>
               <day>11</day>
               <month>04</month>
               <year>2007</year>
            </date>
         </pub>
      </history>
      <cpyrt>
         <year>2007</year>
         <collab>Blangiardo and Richardson; licensee BioMed Central Ltd.</collab>
         <note>This is an open access article distributed under the terms of the Creative Commons Attribution License (<url>http://creativecommons.org/licenses/by/2.0</url>), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.</note>
      </cpyrt>
      <shorttitle>
         <p>Synthesizing results from related experiments</p>
      </shorttitle>
      <shortabs>
         <p>A novel approach for finding a list of features that are commonly perturbed in two or more experiments, quantifying the evidence of dependence between the experiments by a ratio.</p>
      </shortabs>
      <abs>
         <sec>
            <st>
               <p>Abstract</p>
            </st>
            <p>We propose a novel approach for finding a list of features that are commonly perturbed in two or more experiments, quantifying the evidence of dependence between the experiments by a ratio. We present a Bayesian analysis of this ratio, which leads us to suggest two rules for choosing a cut-off on the ranked list of <it>p </it>values. We evaluate and compare the performance of these statistical tools in a simulation study, and show their usefulness on two real datasets.</p>
         </sec>
      </abs>
   </fm>
   <meta>
      <classifications>
         <classification type="BMC" subtype="man_spc_id" id="30010002">Bioinformatics</classification>
         <classification type="BMC" subtype="man_spc_id" id="30010013">Methods</classification>
         <classification type="BMC" subtype="man_spc_id" id="30010010">Genome studies</classification>
      </classifications>
   </meta>
   <bdy>
      <sec>
         <st>
            <p>Background</p>
         </st>
         <p>In the microarray framework researchers are often interested in the comparison of two or more similar experiments that involve different treatments/exposures, tissues, or species. The aim is to find common denominators between these experiments in the form of a parsimonious list of features (for example, genes, biological processes) for which there is strong evidence that the listed features are commonly perturbed in both (all) the experiments and from which to start further investigations. For example, finding common perturbation of a known pathway in several tissues will indicate that this pathway is involved in a systemic response, which is conserved between tissues.</p>
         <p>Ideally, such a problem should involve the joint re-analysis of the two (all) experiments, but this is not always easily feasible (for example, different platforms), and is, in any case, computationally demanding. Alternatively, a natural approach is to consider the ranked list of features derived in each experiment, and to define a process by which a meaningful intersection of the lists can be computed and statistically assessed.</p>
         <p>Methods to synthesize probability measures from several experiments (for example, <it>p </it>values) have been proposed in the literature. Rhodes <it>et al</it>. in 2002 <abbrgrp><abbr bid="B1">1</abbr></abbrgrp> applied Fisher's inverse chi square test to lists of <it>p </it>values from different experiments, with the aim of pooling them together in a meta-analysis. The idea has been improved and enlarged by Hwang <it>et al</it>. <abbrgrp><abbr bid="B2">2</abbr></abbrgrp>, who proposed to assign different weights to different experiments and introduced two more statistics in addition to Fisher's weighted F (Mudholkar-George's weighted T and Liptak-Stouffer's weighted Z). However, as these methods look at evidence of global differential expression across the experiments and define sets of genes based on the global <it>p </it>values, their aim is different from ours: we could say that they are focused on statistically assessing the union of different experiments while we are interested in their intersection.</p>
         <p>The best statistical approach that aims to evaluate the strength of the intersection remains an open question, as discussed recently by Allison <it>et al</it>. <abbrgrp><abbr bid="B3">3</abbr></abbrgrp>. As a first approach, the authors suggest that by using a pre-specified threshold on the <it>p </it>value for differential expression in each experiment, the outcomes of two experiments can be treated as two dichotomous variables. A chi-square test of independence can then be performed to evaluate whether the degree of overlap between experiments is greater than expected by chance. But this way of proceeding is heavily dependent on the choice of a threshold used to dichotomize the outcome of the two experiments and neglects useful information on degrees of evidence of differential expression in each experiment.</p>
         <p>We propose a novel and powerful method for synthesizing such lists that is based on two ideas. Firstly, the departure from the null hypothesis of a chance association between the results of each experiment is characterized by a ratio measuring the relative increase of the number of features in common with respect to the number expected by chance. Secondly, the statistical significance of the ratio is assessed and exploited to propose rules to define synthesized lists.</p>
         <p>For the sake of clarity, from now on we will discuss our methodology in the context of gene expression experiments where the features of interest are genes and the aim is to synthesize lists of differentially expressed genes. But we stress that our methodology is applicable to synthesize ranked lists of any feature of interest from a variety of experiments, as long as each feature is associated with a 'measure of interest' on a probability scale.</p>
         <p>Representing the data in a series of 2 &#215; 2 contingency tables, we first specify a (conditional) model of independence that treats the marginal frequencies in each list as fixed quantities: we calculate the ratio between observed and expected number of genes in common for each table and focus attention on the maximum ratio, that is, the strongest deviation from independence. We propose a permutation based test to assess its significance and discuss some shortcomings of this simple approach.</p>
         <p>We enlarge the scenario by specifying a joint model of the two experiments (treating the marginal frequencies of differential expression in each experiment as random quantities, instead of fixed) that is formulated in a Bayesian framework. Inference can be based on the marginal posterior distribution of the maximum of the ratio of the observed to the expected probability of genes to be in common.</p>
         <p>Note that procedures based on maximum statistics are used in a variety of contexts to focus the analysis on particular subsets of interest; for example, in geographical epidemiology as a way of investigating maximum disease risks around a point source <abbrgrp><abbr bid="B4">4</abbr></abbrgrp>, or for scanning time or spatial windows for clusters of cases <abbrgrp><abbr bid="B5">5</abbr></abbrgrp>. In gene expression studies, maximum-based statistics have been proposed for evaluating if <it>a priori </it>defined gene sets are enriched relative to a list of genes ranked on the basis of their differential expression between two classes <abbrgrp><abbr bid="B6">6</abbr></abbrgrp>.</p>
         <p>Focusing on the maximal ratio we are not aiming at finding the largest list of genes in common, but we are interested in a parsimonious list associated with the strongest evidence of dependence between experiments. However, by being very specific (few false positives), this procedure tends to be rather conservative and to be associated with a narrow list of genes in common. To increase sensitivity and account for larger lists, we propose a second rule that focuses attention on the list associated with a ratio equal to or greater than two. We show in our simulations that this rule leads to a good compromise of false positives and false negatives, indicating very high specificity and good sensitivity. It is also close to achieving the minimum of the total error (sum of false positives and false negatives).</p>
         <p>We evaluate the performance of our methodology on simulated data and compare the results to those obtained using Hwang <it>et al</it>.'s approach. Then, we apply our method to two real case studies, highlighting the biological interest of the obtained results.</p>
      </sec>
      <sec>
         <st>
            <p>Results</p>
         </st>
         <p>We demonstrate the statistical and biological potential of our methodology using simulated data and publicly available datasets. For the simulation we follow the setup described in <abbrgrp><abbr bid="B2">2</abbr></abbrgrp>. The first real example uses public data from an experiment that evaluates the effect of mechanical ventilation on lung gene expression of mice and rats. The second real example uses public data from an experiment that evaluates the effect of high fat diet on fat and skeletal muscle of mice.</p>
         <sec>
            <st>
               <p>2 &#215; 2 Table: conditional model for two experiments</p>
            </st>
            <p>Suppose we want to compare the results of two microarray experiments, each of them reporting for the same set of <it>n </it>genes a measure of differential expression on a probability scale (for example, <it>p </it>value; Table <tblr tid="T1">1</tblr>).</p>
            <tbl id="T1">
               <title>
                  <p>Table 1</p>
               </title>
               <caption>
                  <p>Lists of <it>p </it>values for two experiments</p>
               </caption>
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                  <r>
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                        <p>Experiment A</p>
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            <p>We rank the genes according to the recorded probability measures. For each cut-off <it>q</it>,(0 &#8804; <it>q </it>&#8804; 1), we obtain the number of differentially expressed genes for each of the two lists as <it>O</it><sub>1+</sub>(<it>q</it>) and <it>O</it><sub>+1</sub>(<it>q</it>) and the number <it>O</it><sub>11</sub>(<it>q</it>) of differentially expressed genes in common between the two experiments (Table <tblr tid="T2">2</tblr>). The threshold <it>q </it>is a continuous variable but, in practice, we consider a discretization of <it>q</it>. In the present paper, we specify a vector <it>q </it>= (<it>q</it><sub>0 </sub>= 0, <it>q</it><sub>1 </sub>= 0.001. ..., <it>q</it>, ..., <it>q</it><sub><it>k </it></sub>= 1), formed by <it>K </it>= 101 elements, but other discretizations can be used without loss of generality. For a threshold <it>q</it>, under the hypothesis of independence of the contrasts investigated by the two experiments, the number of genes in common by chance is calculated as:</p>
            <tbl id="T2">
               <title>
                  <p>Table 2</p>
               </title>
               <caption>
                  <p>Contingency table for experiment A and experiment B, given a threshold <it>q</it></p>
               </caption>
               <tblbdy cols="5">
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
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                        <p>Experiment B</p>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c cspan="2">
                        <hr/>
                     </c>
                     <c>
                        <p/>
                     </c>
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                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
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                        <p>
                           <it>DE</it>
                        </p>
                     </c>
                     <c ca="center">
                        <p>
                           <it>Non DE</it>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c cspan="5">
                        <hr/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>Experiment A</p>
                     </c>
                     <c ca="center">
                        <p>
                           <it>DE</it>
                        </p>
                     </c>
                     <c ca="center">
                        <p><it>O</it><sub>11</sub>(<it>q</it>)</p>
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                        <p><it>O</it><sub>1+</sub>(<it>q</it>) - <it>O</it><sub>11</sub>(<it>q</it>)</p>
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                        <p><it>O</it><sub>1+</sub>(<it>q</it>)</p>
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                  <r>
                     <c>
                        <p/>
                     </c>
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                        <p>
                           <it>Non DE</it>
                        </p>
                     </c>
                     <c ca="center">
                        <p><it>O</it><sub>+1</sub>(<it>q</it>) - <it>O</it><sub>11</sub>(<it>q</it>)</p>
                     </c>
                     <c ca="center">
                        <p><it>n </it>- <it>O</it><sub>1+</sub>(<it>q</it>) - <it>O</it><sub>+1</sub>(<it>q</it>) + <it>O</it><sub>11</sub>(<it>q</it>)</p>
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                        <p><it>n </it>- <it>O</it><sub>1+</sub>(<it>q</it>)</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
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                        <p/>
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                        <p><it>O</it><sub>+1</sub>(<it>q</it>)</p>
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                        <p><it>n </it>- <it>O</it><sub>+1</sub>(<it>q</it>)</p>
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                        <p>
                           <it>n</it>
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               </tblbdy>
               <tblfn>
                  <p><it>n </it>is the total number of genes and <it>O</it><sub>11</sub>(<it>q</it>) is the number of genes in common. DE, differentially expressed. Non DE, non differentially expressed</p>
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 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaadaWcaaqaaiaad+eadaWgaaWcbaGaaGymaiabgUcaRaqabaGccaGGOaGaamyCaiaacMcacqGHxdaTcaWGpbWaaSbaaSqaaiabgUcaRiaaigdaaeqaaOGaaiikaiaadghacaGGPaaabaGaamOBaaaaaaa@4033@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>In the 2 &#215; 2 Table, where the marginal frequencies <it>O</it><sub>1+</sub>(<it>q</it>), <it>O</it><sub>+1</sub>(<it>q</it>) and the total number of genes <it>n </it>are assumed fixed quantities, given <it>q</it>, the only random variable is <it>O</it><sub>11</sub>(<it>q</it>).</p>
            <p>The conditional distribution of <it>O</it><sub>11</sub>(<it>q</it>) is hypergeometric <abbrgrp><abbr bid="B7">7</abbr></abbrgrp>:</p>
            <p>
               <display-formula id="M1"><it>O</it><sub>11</sub>(<it>q</it>) ~ <it>Hyper</it>(<it>O</it><sub>1+</sub>(<it>q</it>), <it>O</it><sub>+1</sub>(<it>q</it>), <it>n</it>).</display-formula>
            </p>
            <p>We then calculate the statistic <it>T</it>(<it>q</it>) as the observed to expected ratio:</p>
            <p>
               <display-formula id="M2">
                  <m:math name="gb-2007-8-4-r54-i8" xmlns:m="http://www.w3.org/1998/Math/MathML">
                     <m:semantics>
                        <m:mrow>
                           <m:mi>T</m:mi>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>=</m:mo>
                           <m:mfrac>
                              <m:mrow>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>11</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                              <m:mrow>
                                 <m:mfrac>
                                    <m:mrow>
                                       <m:msub>
                                          <m:mi>O</m:mi>
                                          <m:mrow>
                                             <m:mn>1</m:mn>
                                             <m:mo>+</m:mo>
                                          </m:mrow>
                                       </m:msub>
                                       <m:mo stretchy="false">(</m:mo>
                                       <m:mi>q</m:mi>
                                       <m:mo stretchy="false">)</m:mo>
                                       <m:mo>&#215;</m:mo>
                                       <m:msub>
                                          <m:mi>O</m:mi>
                                          <m:mrow>
                                             <m:mo>+</m:mo>
                                             <m:mn>1</m:mn>
                                          </m:mrow>
                                       </m:msub>
                                       <m:mo stretchy="false">(</m:mo>
                                       <m:mi>q</m:mi>
                                       <m:mo stretchy="false">)</m:mo>
                                    </m:mrow>
                                    <m:mi>n</m:mi>
                                 </m:mfrac>
                              </m:mrow>
                           </m:mfrac>
                           <m:mo>.</m:mo>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaacaWGubGaaiikaiaadghacaGGPaGaeyypa0ZaaSaaaeaacaWGpbWaaSbaaSqaaiaaigdacaaIXaaabeaakiaacIcacaWGXbGaaiykaaqaamaalaaabaGaam4tamaaBaaaleaacaaIXaGaey4kaScabeaakiaacIcacaWGXbGaaiykaiabgEna0kaad+eadaWgaaWcbaGaey4kaSIaaGymaaqabaGccaGGOaGaamyCaiaacMcaaeaacaWGUbaaaaaacaGGUaaaaa@49F2@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>In other words, <it>T</it>(<it>q</it>) quantifies the strength of association between lists at cut-off <it>q </it>in terms of ratio of observed to expected. The denominator is a fixed quantity, so the distribution of <it>T</it>(<it>q</it>) is also proportional to a hypergeometric distribution:</p>
            <p>
               <display-formula><it>T</it><sub>q </sub>&#8733; <it>Hyper</it>(<it>O</it><sub>1+</sub>(<it>q</it>), <it>O</it><sub>+1</sub>(<it>q</it>), <it>n</it>)</display-formula>
            </p>
            <p>with mean and variance:</p>
            <p>
               <display-formula><it>E</it>(<it>T</it>(<it>q</it>)|<it>O</it><sub>1+</sub>(<it>q</it>), <it>O</it><sub>+1</sub>(<it>q</it>), <it>n</it>) = 1</display-formula>
            </p>
            <p>
               <display-formula>
                  <m:math name="gb-2007-8-4-r54-i9" xmlns:m="http://www.w3.org/1998/Math/MathML">
                     <m:semantics>
                        <m:mrow>
                           <m:mi>V</m:mi>
                           <m:mi>a</m:mi>
                           <m:mi>r</m:mi>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>T</m:mi>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>|</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>1</m:mn>
                                 <m:mo>+</m:mo>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>,</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mo>+</m:mo>
                                 <m:mn>1</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>,</m:mo>
                           <m:mi>n</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>=</m:mo>
                           <m:mrow>
                              <m:mo>(</m:mo>
                              <m:mrow>
                                 <m:mn>1</m:mn>
                                 <m:mo>&#8722;</m:mo>
                                 <m:mfrac>
                                    <m:mrow>
                                       <m:msub>
                                          <m:mi>O</m:mi>
                                          <m:mrow>
                                             <m:mn>1</m:mn>
                                             <m:mo>+</m:mo>
                                          </m:mrow>
                                       </m:msub>
                                       <m:mo stretchy="false">(</m:mo>
                                       <m:mi>q</m:mi>
                                       <m:mo stretchy="false">)</m:mo>
                                    </m:mrow>
                                    <m:mi>n</m:mi>
                                 </m:mfrac>
                              </m:mrow>
                              <m:mo>)</m:mo>
                           </m:mrow>
                           <m:mo>&#215;</m:mo>
                           <m:mrow>
                              <m:mo>(</m:mo>
                              <m:mrow>
                                 <m:mfrac>
                                    <m:mrow>
                                       <m:mi>n</m:mi>
                                       <m:mo>&#8722;</m:mo>
                                       <m:msub>
                                          <m:mi>O</m:mi>
                                          <m:mrow>
                                             <m:mo>+</m:mo>
                                             <m:mn>1</m:mn>
                                          </m:mrow>
                                       </m:msub>
                                       <m:mo stretchy="false">(</m:mo>
                                       <m:mi>q</m:mi>
                                       <m:mo stretchy="false">)</m:mo>
                                    </m:mrow>
                                    <m:mrow>
                                       <m:mi>n</m:mi>
                                       <m:mo>&#8722;</m:mo>
                                       <m:mn>1</m:mn>
                                    </m:mrow>
                                 </m:mfrac>
                              </m:mrow>
                              <m:mo>)</m:mo>
                           </m:mrow>
                           <m:mo>.</m:mo>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=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@5FA8@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>Throughout, we use the symbol | to denote conditioning, thus <it>E</it>(<it>T</it>(<it>q</it>)|<it>O</it><sub>1+</sub>(<it>q</it>), <it>O</it><sub>+1</sub>(<it>q</it>), <it>n</it>) indicates the conditional expectation of <it>T</it>(<it>q</it>) given <it>O</it><sub>1+</sub>(<it>q</it>), <it>O</it><sub>+1</sub>(<it>q</it>) and <it>n</it>.</p>
            <p>As a first step, we focus attention on the ordinal statistic <it>T</it>(<it>q</it><sub><it>max</it></sub>) &#8801; <it>max</it><sub><it>q</it></sub><it>T</it>(<it>q</it>), which represents the maximal deviation from the null model of independence between the two experiments, or equivalently the largest relative increase of the number of genes in common. This maximum value is associated with a threshold <it>q</it><sub>max </sub>on the probability measure and with a number <it>O</it><sub>11</sub>(<it>q</it><sub>max</sub>) of genes in common, which can be selected for further investigations and mined for relevant biological pathways.</p>
            <p>The exact distribution of <it>T</it>(<it>q</it><sub>max</sub>) is not easily obtained, since the series of 2 &#215; 2 tables are not independent. We thus suggest performing a Monte Carlo permutation test of <it>T</it>(<it>q</it>) under the null hypothesis of independence between the two experiments. To be precise, the probability measures of one list are randomly permuted <it>S </it>times, while those of the other list are kept fixed, leading to <it>S </it>values of the statistic <it>T</it><sup><it>S</it></sup>(<it>q</it><sub><it>max</it></sub>), which represent the null distribution of <it>T</it>(<it>q</it><sub>max</sub>). From these, a Monte Carlo <it>p </it>value for the observed value of <it>T</it>(<it>q</it><sub>max</sub>) can be computed and the choice of <it>S </it>adapted to the required degree of precision.</p>
         </sec>
         <sec>
            <st>
               <p>2 &#215; 2 Table: joint model of two experiments</p>
            </st>
            <p>For extreme values of the threshold <it>q </it>(<it>q </it>&#8773; 0), <it>O</it><sub>1+</sub>(<it>q</it>) and <it>O</it><sub>+1</sub>(<it>q</it>) can be very small. In this case, the denominator of <it>T</it>(<it>q</it>) assumes values smaller than 1 and <it>T</it>(<it>q</it>) explodes, leading to unreliable estimates of the ratio. In addition, the hypergeometric sampling model specified for <it>T</it>(<it>q</it><sub>max</sub>) in our previous procedure does not take into account the uncertainty of the margins of the table (since they are all considered fixed).</p>
            <p>To address these issues and to improve our statistical procedure, we thus propose to consider a joint model of the experiments, which also treats <it>O</it><sub>1+</sub>(<it>q</it>) and <it>O</it><sub>+1</sub>(<it>q</it>) as random variables, releasing the conditioning. Furthermore, we specify this in a Bayesian framework, where the underlying probabilities,</p>
            <p>
               <display-formula>
                  <m:math name="gb-2007-8-4-r54-i10" xmlns:m="http://www.w3.org/1998/Math/MathML">
                     <m:semantics>
                        <m:mrow>
                           <m:msub>
                              <m:mi>&#952;</m:mi>
                              <m:mi>i</m:mi>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>,</m:mo>
                           <m:mn>1</m:mn>
                           <m:mo>&#8804;</m:mo>
                           <m:mi>i</m:mi>
                           <m:mo>&#8804;</m:mo>
                           <m:mn>4</m:mn>
                           <m:mo>,</m:mo>
                           <m:mstyle displaystyle="true">
                              <m:munderover>
                                 <m:mo>&#8721;</m:mo>
                                 <m:mrow>
                                    <m:mi>i</m:mi>
                                    <m:mo>=</m:mo>
                                    <m:mn>1</m:mn>
                                 </m:mrow>
                                 <m:mn>4</m:mn>
                              </m:munderover>
                              <m:mrow>
                                 <m:msub>
                                    <m:mi>&#952;</m:mi>
                                    <m:mi>i</m:mi>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                           </m:mstyle>
                           <m:mo>=</m:mo>
                           <m:mn>1</m:mn>
                           <m:mo>,</m:mo>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaaiiGacqWF4oqCdaWgaaWcbaGaamyAaaqabaGccaGGOaGaamyCaiaacMcacaGGSaGaaGymaiabgsMiJkaadMgacqGHKjYOcaaI0aGaaiilamaaqahabaGae8hUde3aaSbaaSqaaiaadMgaaeqaaOGaaiikaiaadghacaGGPaaaleaacaWGPbGaeyypa0JaaGymaaqaaiaaisdaa0GaeyyeIuoakiabg2da9iaaigdacaGGSaaaaa@4CDC@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>for the four cells in the 2 &#215; 2 contingency table (indexes from left to right) are given a prior distribution. In this way, we account for the variability in <it>O</it><sub>1+</sub>(<it>q</it>) and <it>O</it><sub>+1</sub>(<it>q</it>) and smooth the ratio <it>T</it>(<it>q</it>) for extreme, small values of <it>q</it>.</p>
            <p>Starting from Table <tblr tid="T2">2</tblr>, we model the observed frequencies as arising from a multinomial distribution:</p>
            <p>
               <display-formula id="M3">
                  <m:math name="gb-2007-8-4-r54-i11" xmlns:m="http://www.w3.org/1998/Math/MathML">
                     <m:semantics>
                        <m:mrow>
                           <m:mi>M</m:mi>
                           <m:mi>u</m:mi>
                           <m:mi>l</m:mi>
                           <m:mi>t</m:mi>
                           <m:mi>i</m:mi>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>O</m:mi>
                           <m:mo>|</m:mo>
                           <m:mi>&#952;</m:mi>
                           <m:mo>,</m:mo>
                           <m:mi>n</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mi>&#945;</m:mi>
                           <m:msub>
                              <m:mi>&#952;</m:mi>
                              <m:mn>1</m:mn>
                           </m:msub>
                           <m:msup>
                              <m:mrow>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                              <m:mrow>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>11</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                           </m:msup>
                           <m:mo>&#215;</m:mo>
                           <m:msub>
                              <m:mi>&#952;</m:mi>
                              <m:mn>2</m:mn>
                           </m:msub>
                           <m:msup>
                              <m:mrow>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                              <m:mrow>
                                 <m:mo stretchy="false">[</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>1</m:mn>
                                       <m:mo>+</m:mo>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>&#8722;</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>11</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo stretchy="false">]</m:mo>
                              </m:mrow>
                           </m:msup>
                           <m:mo>&#215;</m:mo>
                           <m:msub>
                              <m:mi>&#952;</m:mi>
                              <m:mn>3</m:mn>
                           </m:msub>
                           <m:msup>
                              <m:mrow>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                              <m:mrow>
                                 <m:mo stretchy="false">[</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mo>+</m:mo>
                                       <m:mn>1</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>&#8722;</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>11</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo stretchy="false">]</m:mo>
                              </m:mrow>
                           </m:msup>
                           <m:mo>&#215;</m:mo>
                           <m:msub>
                              <m:mi>&#952;</m:mi>
                              <m:mn>4</m:mn>
                           </m:msub>
                           <m:msup>
                              <m:mrow>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                              <m:mrow>
                                 <m:mo stretchy="false">[</m:mo>
                                 <m:mi>n</m:mi>
                                 <m:mo>&#8722;</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>1</m:mn>
                                       <m:mo>+</m:mo>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>&#8722;</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mo>+</m:mo>
                                       <m:mn>1</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>+</m:mo>
                                 <m:msub>
                                    <m:mi>O</m:mi>
                                    <m:mrow>
                                       <m:mn>11</m:mn>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo stretchy="false">]</m:mo>
                              </m:mrow>
                           </m:msup>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
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                  </m:math>
               </display-formula>
            </p>
            <p>Since we are in a Bayesian framework, we need to specify a prior distribution for all the parameters. The vector of parameters <it>&#952;</it>(<it>q</it>) is modeled as arising from a Dirichlet distribution <abbrgrp><abbr bid="B8">8</abbr></abbrgrp>:</p>
            <p>
               <display-formula><it>&#952;</it>(<it>q</it>) ~ <it>Dir</it>(<it>a</it>, <it>a</it>, <it>a</it>, <it>a</it>), <it>a </it>= 0.05,</display-formula>
            </p>
            <p>which ensures the constraint <inline-formula><m:math name="gb-2007-8-4-r54-i12" xmlns:m="http://www.w3.org/1998/Math/MathML"><m:semantics><m:mrow><m:mstyle displaystyle="true"><m:msubsup><m:mo>&#8721;</m:mo><m:mrow><m:mi>i</m:mi><m:mo>=</m:mo><m:mn>1</m:mn></m:mrow><m:mn>4</m:mn></m:msubsup><m:mrow><m:msub><m:mi>&#952;</m:mi><m:mi>i</m:mi></m:msub><m:mo stretchy="false">(</m:mo><m:mi>q</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo><m:mn>1</m:mn></m:mrow></m:mstyle></m:mrow><m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaadaaeWaqaaGGaciab=H7aXnaaBaaaleaacaWGPbaabeaakiaacIcacaWGXbGaaiykaiabg2da9iaaigdaaSqaaiaadMgacqGH9aqpcaaIXaaabaGaaGinaaqdcqGHris5aaaa@3F8D@</m:annotation></m:semantics></m:math></inline-formula>.</p>
            <p>The derived quantity of interest is, as before, the ratio of the probability that a differentially expressed gene is truly common for both experiments, to the probability that a gene is included in the common list by chance:</p>
            <p>
               <display-formula id="M4">
                  <m:math name="gb-2007-8-4-r54-i13" xmlns:m="http://www.w3.org/1998/Math/MathML">
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                           <m:mi>R</m:mi>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>=</m:mo>
                           <m:mfrac>
                              <m:mrow>
                                 <m:msub>
                                    <m:mi>&#952;</m:mi>
                                    <m:mn>1</m:mn>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                              <m:mrow>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:msub>
                                    <m:mi>&#952;</m:mi>
                                    <m:mn>1</m:mn>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>+</m:mo>
                                 <m:msub>
                                    <m:mi>&#952;</m:mi>
                                    <m:mn>2</m:mn>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>&#215;</m:mo>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:msub>
                                    <m:mi>&#952;</m:mi>
                                    <m:mn>1</m:mn>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo>+</m:mo>
                                 <m:msub>
                                    <m:mi>&#952;</m:mi>
                                    <m:mn>3</m:mn>
                                 </m:msub>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:mi>q</m:mi>
                                 <m:mo stretchy="false">)</m:mo>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                           </m:mfrac>
                           <m:mo>.</m:mo>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaacaWGsbGaaiikaiaadghacaGGPaGaeyypa0ZaaSaaaeaacqaH4oqCdaWgaaWcbaGaaGymaaqabaGccaGGOaGaamyCaiaacMcaaeaacaGGOaGaeqiUde3aaSbaaSqaaiaaigdaaeqaaOGaaiikaiaadghacaGGPaGaey4kaSIaeqiUde3aaSbaaSqaaiaaikdaaeqaaOGaaiikaiaadghacaGGPaGaaiykaiabgEna0kaacIcacqaH4oqCdaWgaaWcbaGaaGymaaqabaGccaGGOaGaamyCaiaacMcacqGHRaWkcqaH4oqCdaWgaaWcbaGaaG4maaqabaGccaGGOaGaamyCaiaacMcacaGGPaaaaiaac6caaaa@5779@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>The Dirichlet prior is conjugate for the multinomial likelihood <abbrgrp><abbr bid="B8">8</abbr></abbrgrp> and the posterior distribution of <it>&#952;</it>(<it>q</it>)|<b><it>O</it></b>, <it>n </it>is again a Dirichlet distribution, given by:</p>
            <p>
               <display-formula id="M5">
                  <m:math name="gb-2007-8-4-r54-i14" xmlns:m="http://www.w3.org/1998/Math/MathML">
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                        <m:mrow>
                           <m:mi>&#952;</m:mi>
                           <m:mo>|</m:mo>
                           <m:mi>O</m:mi>
                           <m:mo>,</m:mo>
                           <m:mi>n</m:mi>
                           <m:mo>~</m:mo>
                           <m:mi>D</m:mi>
                           <m:mi>i</m:mi>
                           <m:mi>r</m:mi>
                           <m:mo stretchy="false">(</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>11</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>+</m:mo>
                           <m:mi>a</m:mi>
                           <m:mo>,</m:mo>
                           <m:mo stretchy="false">[</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>1</m:mn>
                                 <m:mo>+</m:mo>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>&#8722;</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>11</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo stretchy="false">]</m:mo>
                           <m:mo>+</m:mo>
                           <m:mi>a</m:mi>
                           <m:mo>,</m:mo>
                           <m:mo stretchy="false">[</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mo>+</m:mo>
                                 <m:mn>1</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>&#8722;</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>11</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo stretchy="false">]</m:mo>
                           <m:mo>+</m:mo>
                           <m:mi>a</m:mi>
                           <m:mo>,</m:mo>
                           <m:mo stretchy="false">[</m:mo>
                           <m:mi>n</m:mi>
                           <m:mo>&#8722;</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>1</m:mn>
                                 <m:mo>+</m:mo>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>&#8722;</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mo>+</m:mo>
                                 <m:mn>1</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo>+</m:mo>
                           <m:msub>
                              <m:mi>O</m:mi>
                              <m:mrow>
                                 <m:mn>11</m:mn>
                              </m:mrow>
                           </m:msub>
                           <m:mo stretchy="false">(</m:mo>
                           <m:mi>q</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                           <m:mo stretchy="false">]</m:mo>
                           <m:mo>+</m:mo>
                           <m:mi>a</m:mi>
                           <m:mo stretchy="false">)</m:mo>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=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@7876@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>This distribution is easily sampled from using standard algorithms. Note that the prior weights <it>a </it>= 0.05 can be interpreted as the number of hypothetical counts in each cell observed prior to the investigation. Further, it can be shown that the variance of the vector of probabilities in the Dirichlet distribution increases as the prior weights tend to zero. Thus, our choice of value of 0.05 for the prior weights allows both high variability and a small influence of the prior specification on the posterior distribution of <it>&#952;</it>(<it>q</it>). The posterior distribution of <it>R</it>(<it>q</it>)|<b><it>O</it></b>, <it>n </it>can be easily derived from that of <it>&#952;</it>(<it>q</it>) using for example a sample of values of <it>&#952;</it>(<it>q</it>), generated from the posterior distribution (equation 5). In particular, from a sample of values of <it>R</it>(<it>q</it>)|<b><it>O</it></b>, <it>n</it>, the 95% two sided credibility interval, CI<sub>95</sub>(q), can be easily computed, for each <it>R</it>(<it>q</it>).</p>
         </sec>
         <sec>
            <st>
               <p>2 &#215; 2 Table: decision rules for intersection</p>
            </st>
            <p>In the Bayesian context, several decision rules can be envisaged to choose the threshold corresponding to the common list showing a clear evidence of association between experiments. The general principle is as follows: first, select a ratio <it>R</it>(<it>q</it>) according to a decision rule; second, consider the threshold <it>q </it>corresponding to the selected ratio; and third, return the list <it>O</it><sub>11</sub>(<it>q</it>), that is, the intersection of the lists for the threshold <it>q</it>. Figure <figr fid="F1">1</figr> (right) shows a typical plot of <it>R</it>(<it>q</it>) and its credibility interval as a function of <it>q </it>in case of associated experiments (a different shape for <it>R</it>(<it>q</it>) is presented in Additional data file 1). As the <it>p </it>value increases, the ratio <it>R</it>(<it>q</it>) decreases and the associated list of common genes <it>O</it><sub>11</sub>(<it>q</it>) becomes larger (the number of genes in common for each ratio is indicated on the right axis of the plot). We need a rule to select a threshold on the <it>p </it>value and the corresponding list of genes in common. To this purpose we now discuss two decision rules.</p>
            <fig id="F1">
               <title>
                  <p>Figure 1</p>
               </title>
               <caption>
                  <p>Typical plots of <it>T</it>(<it>q</it>) and <it>R</it>(<it>q</it>) for associated experiments (case A1)</p>
               </caption>
               <text>
                  <p>Typical plots of <it>T</it>(<it>q</it>) and <it>R</it>(<it>q</it>) for associated experiments (case A1). The two associated experiments were simulated under scenario I, structure A, with true differences drawn from a <it>Ga</it>(2.5,0.4) and noise experiment specific of 0.5 and 0.8, respectively (signal-to-noise ratio = 9.6). The left plot shows the distribution of <it>T</it>(<it>q</it>) and the right one shows the distribution of <it>R</it>(<it>q</it>) with Bayesian credibility intervals at 95%. <it>T</it>(<it>q</it>) shows a deviation from 1 for a <it>p </it>value between 0.01 and 0.5. T(q<sub>max</sub>) is 2.6 and corresponds to a threshold <it>q </it>= 0.01. <it>R</it>(<it>q</it>) presents the same trend, but the estimates are slightly smaller since the model takes into account the variability of the margins of the 2 &#215; 2 table. The threshold associated with <it>R</it>(<it>q</it>) = 2 is 0.08. The number of genes in common for each ratio <it>R</it>(<it>q</it>) is reported on the right axis of each plot.</p>
               </text>
               <graphic file="gb-2007-8-4-r54-1"/>
            </fig>
            <p>Under the null model of no association between the experiments, <it>Median</it>(<it>R</it>(<it>q</it>)|<it>H</it><sub>0</sub>) = 1, so we consider <it>R</it>(<it>q</it>) as indicating departure from independence if its credibility interval does not contain 1.</p>
            <p>As an extension of <it>T</it>(<it>q</it><sub>max</sub>) we thus propose to consider the maximum of <it>Median</it>(<it>R</it>(<it>q</it>)|<b><it>O</it></b>, <it>n</it>) only for the subset of credibility intervals that do not include 1 and define:</p>
            <p>
               <display-formula id="M6">q<sub>max </sub>= argmax{<it>Median</it>(<it>R</it>(<it>q</it>)|<b><it>O</it></b>, <it>n</it>) over the set of values of <it>q </it>for which <it>CI</it><sub>95</sub>(<it>q</it>) excludes 1}.</display-formula>
            </p>
            <p>In other words, <it>q</it><sub>max </sub>is defined to be the threshold associated with the maximum of the ratio, which we denote <it>R</it>(<it>q</it><sub>max</sub>). If all credibility intervals contain 1, the maximum of <it>R</it>(<it>q</it>) can still be computed, but we do not associate it with a list since there is no departure from independence that could be considered significant.</p>
            <p>Note that in the Bayesian context many <it>R</it>(<it>q</it>) can have a CI that excludes 1 and they all represent a significant deviation from the independence. An advantage of the maximum statistic is that it returns a list of interesting features with few false positives (FP), as will be shown later in the simulations. On the other hand, this list is usually rather small and in cases where the level of noise is substantial it excludes a large number of true positives (TP), for which the evidence is less strong.</p>
            <p>We next consider an alternative to the max ratio: the largest threshold <it>q </it>for which the ratio <it>R</it>(<it>q</it>) &#8805; 2. It is the largest threshold where the number of genes called in common at least doubles the number of genes in common under independence:</p>
            <p>
               <display-formula id="M7"><it>q</it><sub>2 </sub>= max{over the set of values of <it>q </it>for which <it>Median</it>(<it>R</it>(<it>q</it>)|<b><it>O</it></b>, <it>n</it>) &#8805; 2 and <it>CI</it><sub>95</sub>(<it>q</it>) excludes 1}.</display-formula>
            </p>
            <p>Using this rule provides a fair balance between specificity and sensitivity as we will show later. Indeed, it is expected that when going beyond this point to larger values of <it>q</it>, the marginal benefit of adding a few more true positives and of reducing the false negatives (FN) to the list will be outweighed by the expected larger number of false positives that would also be added. By our simulations we show indeed that this rule is close to giving the minimal global error (FP + FN).</p>
            <p>Figure <figr fid="F2">2</figr> (top) plots the false discovery rate:</p>
            <fig id="F2">
               <title>
                  <p>Figure 2</p>
               </title>
               <caption>
                  <p>Misclassification error, false discovery and false non-discovery rates for case A2 (results are averaged over 50 replicates)</p>
               </caption>
               <text>
                  <p>Misclassification error, false discovery and false non-discovery rates for case A2 (results are averaged over 50 replicates). The upper plot shows the false discovery rate (FDR) and the false non-discovery rate (FNR) for case A2. The FDR is calculated as the ratio of the false positives to the number of genes called in common, while the FDR is calculated as the ratio of the false negatives to the number of genes not called in common. The true differences <it>d</it><sub><it>g </it></sub>are drawn from a <it>Ga</it>(2, 0.5) and the noise component experiment specific is 2 for the first experiment and 3 for the second. R(q<sub>max</sub>) shows the minimum FDR. On the other hand, R(q<sub>min</sub>) has a very large FDR and the improvement of the FNR is slight. As a compromise, the threshold q<sub>2 </sub>is close to q<sub>max</sub>, so guarantees a low FDR, but returns a larger list. It approximatively corresponds to the intersection point between the two curves of FDR and FNR. The lower plot shows the global error as the sum of FP and FN. The threshold associated with R(q<sub>2</sub>) is very close to the minimum of the curve, that is, to the smallest global misclassification error.</p>
               </text>
               <graphic file="gb-2007-8-4-r54-2"/>
            </fig>
            <p>
               <display-formula>FDR = <it>FP</it>(<it>q</it>)/<it>O</it><sub>11</sub>(<it>q</it>)</display-formula>
            </p>
            <p>and false non-discovery rate:</p>
            <p>
               <display-formula>FNR = <it>FN</it>(<it>q</it>)/(<it>n </it>- <it>O</it><sub>11</sub>(<it>q</it>))</display-formula>
            </p>
            <p>for 50 simulations carried out as described in Materials and methods, for scenario I structure A. It is clear that <it>R</it>(<it>q</it><sub>max</sub>) has the smallest FDR. On the other hand, <it>q</it><sub>2 </sub>corresponds to the intersection between FDR and FNR. Moreover, in Figure <figr fid="F2">2</figr> (bottom) we show that the same threshold minimizes the global misclassification error as the sum of false positives and false negatives. Note that if we considered the minimum significant ratio, defined as the minimum of the <it>R</it>(<it>q</it>) over the set of credibility intervals excluding 1, FDR would increase dramatically and the FNR would decrease only marginally with respect to <it>R</it>(<it>q</it><sub>max</sub>) and <it>R</it>(<it>q</it><sub>2</sub>). As expected, the global misclassification error would also be much larger, making this rule inappropriate.</p>
            <p>When there are no ratios <it>R</it>(<it>q</it>) equal or greater than 2 (which can happen in the case of large noise or when there is only a small proportion of genes in common), this rule does not apply and we recommend using the rule corresponding to <it>R</it>(<it>q</it><sub>max</sub>).</p>
            <p>Our computations have been implemented in the statistical programming language R <abbrgrp><abbr bid="B9">9</abbr></abbrgrp>. The R package for simulating the data, for the two tests and for visualizing the results is called BGcom and is available on our project BGX website <abbrgrp><abbr bid="B10">10</abbr></abbrgrp>.</p>
         </sec>
         <sec>
            <st>
               <p>Performance on simulated data</p>
            </st>
            <p>Besides assessing the operating characteristics of our proposed rules, we also applied the method proposed by Hwang <it>et al</it>. implemented in Matlab <abbrgrp><abbr bid="B11">11</abbr></abbrgrp>. Note that their aim is to integrate <it>p </it>values from different experiments in a meta-analysis and they present three statistics to do so: Fisher's weighted F, Mudholkar-George's weighted T and Liptak-Stouffer's weighted Z. We report Fisher's weighted F (the default statistic in the Matlab function), defined as:</p>
            <p>
               <display-formula>
                  <m:math name="gb-2007-8-4-r54-i15" xmlns:m="http://www.w3.org/1998/Math/MathML">
                     <m:semantics>
                        <m:mrow>
                           <m:msub>
                              <m:mi>F</m:mi>
                              <m:mi>g</m:mi>
                           </m:msub>
                           <m:mo>=</m:mo>
                           <m:mo>&#8722;</m:mo>
                           <m:mn>2</m:mn>
                           <m:mstyle displaystyle="true">
                              <m:msubsup>
                                 <m:mo>&#8721;</m:mo>
                                 <m:mrow>
                                    <m:mi>k</m:mi>
                                    <m:mo>=</m:mo>
                                    <m:mn>1</m:mn>
                                 </m:mrow>
                                 <m:mn>2</m:mn>
                              </m:msubsup>
                              <m:mrow>
                                 <m:msub>
                                    <m:mi>w</m:mi>
                                    <m:mi>k</m:mi>
                                 </m:msub>
                                 <m:mi>l</m:mi>
                                 <m:mi>n</m:mi>
                                 <m:mo stretchy="false">(</m:mo>
                                 <m:msub>
                                    <m:mi>p</m:mi>
                                    <m:mrow>
                                       <m:mi>g</m:mi>
                                       <m:mi>k</m:mi>
                                    </m:mrow>
                                 </m:msub>
                                 <m:mo stretchy="false">)</m:mo>
                              </m:mrow>
                           </m:mstyle>
                        </m:mrow>
                        <m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaacaWGgbWaaSbaaSqaaiaadEgaaeqaaOGaeyypa0JaeyOeI0IaaGOmamaaqadabaGaam4DamaaBaaaleaacaWGRbaabeaaieGakiaa=XgacaWFUbGaaiikaiaadchadaWgaaWcbaGaam4zaiaadUgaaeqaaOGaaiykaaWcbaGaam4Aaiabg2da9iaaigdaaeaacaaIYaaaniabggHiLdaaaa@45A1@</m:annotation>
                     </m:semantics>
                  </m:math>
               </display-formula>
            </p>
            <p>where <it>w</it><sub><it>k </it></sub>is the weight for the <it>k</it><sup><it>th </it></sup>experiment and <it>p</it><sub><it>gk </it></sub>is the <it>p </it>value for the gene <it>g </it>in the experiment <it>k</it>. <it>F</it><sub><it>g </it></sub>will be a new global <it>p </it>value that integrates those weights from different experiments. The authors also present several rules to select differentially expressed genes from <it>F</it><sub><it>g</it></sub>, the simplest one using a fixed threshold on the <it>p </it>values equal to 0.05, and others that minimize the number of false positives and false negatives, in a parametric or non-parametric framework. We follow the authors' suggestion and use the non-parametric rule. For more details on the method, see <abbrgrp><abbr bid="B2">2</abbr></abbrgrp>.</p>
            <p>The behavior of <it>T</it>(<it>q</it>) and of the credibility intervals <it>CI</it><sub>95</sub>(<it>q</it>) for a typical simulation are displayed in Figure <figr fid="F1">1</figr> (associated experiments) and Figure <figr fid="F3">3</figr> (independent experiments). When the two experiments are not associated (the number of simulated genes in common is equal to 0), the plot of <it>T</it>(<it>q</it>) for different cut-offs <it>q </it>is, as expected, a horizontal line of height 1, with evidence of noise for small <it>p </it>values. In the same Figure, one sees that all the credibility intervals derived by the Bayesian procedure include the value 1 and have decreasing width as <it>q </it>gets larger, as expected.</p>
            <fig id="F3">
               <title>
                  <p>Figure 3</p>
               </title>
               <caption>
                  <p>Typical plots of <it>T</it>(<it>q</it>) and <it>R</it>(<it>q</it>) in the case of independent experiments</p>
               </caption>
               <text>
                  <p>Typical plots of <it>T</it>(<it>q</it>) and <it>R</it>(<it>q</it>) in the case of independent experiments. The two independent experiments are simulated under scenario I, structure A, with true differences drawn from a <it>Ga</it>(1, 1) and noise experiment specific of 2 and 2.5, respectively (signal-to-noise ratio = 0.4). The left plot shows the distribution of <it>T</it>(<it>q</it>) and the right one shows the distribution of <it>R</it>(<it>q</it>) with Bayesian credibility intervals at 95%. <it>T</it>(<it>q</it>) follows a horizontal line of height 1 (independence between the lists) and presents instability for small <it>p </it>values (left tail). The Bayesian model does not present any significant threshold for which <it>R</it>(<it>q</it>) deviates from 1 and the CI<sub>95 </sub>always includes 1.</p>
               </text>
               <graphic file="gb-2007-8-4-r54-3"/>
            </fig>
            <p>In the case of two independent experiments we never declare any gene to be in common in any of the 50 simulations, so our procedure has no error. On the other hand, Hwang <it>et al</it>.'s method picks up 320 genes on average (Table <tblr tid="T3">3</tblr>, independence case), which are all false positives.</p>
            <tbl id="T3">
               <title>
                  <p>Table 3</p>
               </title>
               <caption>
                  <p>Performance of Hwang <it>et al</it>.'s method on simulated data for scenario I</p>
               </caption>
               <tblbdy cols="9">
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c ca="center">
                        <p>DE</p>
                     </c>
                     <c ca="center">
                        <p>nonDE</p>
                     </c>
                     <c ca="center">
                        <p>FP (%)</p>
                     </c>
                     <c ca="center">
                        <p>TP (%)</p>
                     </c>
                     <c ca="center">
                        <p>FN (%)</p>
                     </c>
                     <c ca="center">
                        <p>TN (%)</p>
                     </c>
                     <c ca="center">
                        <p>Global error</p>
                     </c>
                     <c ca="center">
                        <p>Global error <it>R</it>(<it>q</it><sub>2</sub>)</p>
                     </c>
                  </r>
                  <r>
                     <c cspan="9">
                        <hr/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>Independent case: <it>n </it>= 3000, common = 0, DE1 = 1000, DE2 = 800</b>
                        </p>
                     </c>
                     <c ca="center">
                        <p>320</p>
                     </c>
                     <c ca="center">
                        <p>2,680</p>
                     </c>
                     <c ca="center">
                        <p>320 (10.7)</p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                     <c ca="center">
                        <p>2,680 (89.3)</p>
                     </c>
                     <c ca="center">
                        <p>320</p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>A: <it>n </it>= 3000, common = 700, DE1 = 1000, DE2 = 800</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case A1</p>
                     </c>
                     <c ca="center">
                        <p>1,121</p>
                     </c>
                     <c ca="center">
                        <p>1,879</p>
                     </c>
                     <c ca="center">
                        <p>440 (19.1)</p>
                     </c>
                     <c ca="center">
                        <p>681 (97.3)</p>
                     </c>
                     <c ca="center">
                        <p>19 (2.7)</p>
                     </c>
                     <c ca="center">
                        <p>1,860 (80.9)</p>
                     </c>
                     <c ca="center">
                        <p>459</p>
                     </c>
                     <c ca="center">
                        <p>82</p>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case A2</p>
                     </c>
                     <c ca="center">
                        <p>409</p>
                     </c>
                     <c ca="center">
                        <p>2,591</p>
                     </c>
                     <c ca="center">
                        <p>188 (8.2)</p>
                     </c>
                     <c ca="center">
                        <p>221 (31.6)</p>
                     </c>
                     <c ca="center">
                        <p>479 (68.4)</p>
                     </c>
                     <c ca="center">
                        <p>2,112 (91.8)</p>
                     </c>
                     <c ca="center">
                        <p>667</p>
                     </c>
                     <c ca="center">
                        <p>544</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>B: <it>n </it>= 3000, common = 200, DE1 = 700, DE2 = 500</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case B1</p>
                     </c>
                     <c ca="center">
                        <p>999</p>
                     </c>
                     <c ca="center">
                        <p>2,001</p>
                     </c>
                     <c ca="center">
                        <p>805 (28.8)</p>
                     </c>
                     <c ca="center">
                        <p>194 (97.0)</p>
                     </c>
                     <c ca="center">
                        <p>6 (3.0)</p>
                     </c>
                     <c ca="center">
                        <p>1,996 (71.2)</p>
                     </c>
                     <c ca="center">
                        <p>811</p>
                     </c>
                     <c ca="center">
                        <p>31*</p>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case B2</p>
                     </c>
                     <c ca="center">
                        <p>427</p>
                     </c>
                     <c ca="center">
                        <p>2,573</p>
                     </c>
                     <c ca="center">
                        <p>333 (11.9)</p>
                     </c>
                     <c ca="center">
                        <p>94 (47.0)</p>
                     </c>
                     <c ca="center">
                        <p>106 (53.0)</p>
                     </c>
                     <c ca="center">
                        <p>2,467 (88.1)</p>
                     </c>
                     <c ca="center">
                        <p>439</p>
                     </c>
                     <c ca="center">
                        <p>165</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>C: <it>n </it>= 3000, common = 100, DE1 = 500, DE2 = 400</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case C1</p>
                     </c>
                     <c ca="center">
                        <p>816</p>
                     </c>
                     <c ca="center">
                        <p>2,185</p>
                     </c>
                     <c ca="center">
                        <p>718 (24.8)</p>
                     </c>
                     <c ca="center">
                        <p>97 (97.1)</p>
                     </c>
                     <c ca="center">
                        <p>3 (2.9)</p>
                     </c>
                     <c ca="center">
                        <p>2,182 (75.2)</p>
                     </c>
                     <c ca="center">
                        <p>721</p>
                     </c>
                     <c ca="center">
                        <p>19*</p>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case C2</p>
                     </c>
                     <c ca="center">
                        <p>346</p>
                     </c>
                     <c ca="center">
                        <p>2,654</p>
                     </c>
                     <c ca="center">
                        <p>299 (10.3)</p>
                     </c>
                     <c ca="center">
                        <p>47 (47.0)</p>
                     </c>
                     <c ca="center">
                        <p>53 (53.0)</p>
                     </c>
                     <c ca="center">
                        <p>2,601 (89.7)</p>
                     </c>
                     <c ca="center">
                        <p>352</p>
                     </c>
                     <c ca="center">
                        <p>84</p>
                     </c>
                  </r>
               </tblbdy>
               <tblfn>
                  <p>Average simulation results: we present the results from Hwang <it>et al</it>.'s method on the simulated data under scenario I. DE1 and DE2 are the differentially expressed genes in the first and the second experiment respectively. We used the Fisher's weighted F defined as <inline-formula><m:math name="gb-2007-8-4-r54-i15" xmlns:m="http://www.w3.org/1998/Math/MathML"><m:semantics><m:mrow><m:msub><m:mi>F</m:mi><m:mi>g</m:mi></m:msub><m:mo>=</m:mo><m:mo>&#8722;</m:mo><m:mn>2</m:mn><m:mstyle displaystyle="true"><m:msubsup><m:mo>&#8721;</m:mo><m:mrow><m:mi>k</m:mi><m:mo>=</m:mo><m:mn>1</m:mn></m:mrow><m:mn>2</m:mn></m:msubsup><m:mrow><m:msub><m:mi>w</m:mi><m:mi>k</m:mi></m:msub><m:mi>l</m:mi><m:mi>n</m:mi><m:mo stretchy="false">(</m:mo><m:msub><m:mi>p</m:mi><m:mrow><m:mi>g</m:mi><m:mi>k</m:mi></m:mrow></m:msub><m:mo stretchy="false">)</m:mo></m:mrow></m:mstyle></m:mrow><m:annotation encoding="MathType-MTEF">
 MathType@MTEF@5@5@+=feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbhv2BYDwAHbqedmvETj2BSbqee0evGueE0jxyaibaiKI8=vI8tuQ8FMI8Gi=hEeeu0xXdbba9frFj0=OqFfea0dXdd9vqai=hGuQ8kuc9pgc9s8qqaq=dirpe0xb9q8qiLsFr0=vr0=vr0dc8meaabaqaciGacaGaaeqabaqadeqadaaakeaacaWGgbWaaSbaaSqaaiaadEgaaeqaaOGaeyypa0JaeyOeI0IaaGOmamaaqadabaGaam4DamaaBaaaleaacaWGRbaabeaaieGakiaa=XgacaWFUbGaaiikaiaadchadaWgaaWcbaGaam4zaiaadUgaaeqaaOGaaiykaaWcbaGaam4Aaiabg2da9iaaigdaaeaacaaIYaaaniabggHiLdaaaa@45A1@</m:annotation></m:semantics></m:math></inline-formula>, where <it>w</it><sub><it>k </it></sub>is the weight for the <it>k</it><sup><it>th </it></sup>experiment and <it>p</it><sub><it>gk </it></sub>is the <it>p </it>value for the gene <it>g </it>in the experiment <it>k</it>. We present the non-parametric rule to select the differentially expressed (DE) genes, as suggested by the authors. The method is implemented in Matlab. In the last column we report the Global error (FP + FN) of our procedure for <it>q</it><sub>2 </sub>(see Table 2) for ease of comparison. *There is no ratio larger than 2 so the maximum rule has been used in this case.</p>
               </tblfn>
            </tbl>
            <p>When there is a positive association between the two experiments, <it>T</it>(<it>q</it>) can assume two shapes: it can decrease monotonically as the <it>p </it>values increase (Figure <figr fid="F1">1</figr>), or reach a peak and then decrease (Additional data file 1) as the <it>p </it>values increase. The Bayesian estimates exhibit a similar shape, but since in this approach the variability of the denominator of <it>T</it>(<it>q</it>) is modeled, the resulting ratio estimates are smoothed.</p>
            <p>We see that our proposed method gives a sensible and interpretable procedure, with a pattern that is easily distinguishable from that of the no association case. This is confirmed by the results given in Table <tblr tid="T4">4</tblr>.</p>
            <tbl id="T4">
               <title>
                  <p>Table 4</p>
               </title>
               <caption>
                  <p>Performance on simulated data for scenario I</p>
               </caption>
               <tblbdy cols="13">
                  <r>
                     <c ca="left">
                        <p>Parameters</p>
                     </c>
                     <c ca="left">
                        <p>Rules</p>
                     </c>
                     <c ca="center">
                        <p>q</p>
                     </c>
                     <c ca="center">
                        <p>R</p>
                     </c>
                     <c ca="center">
                        <p>
                           <it>CI</it>
                           <sub>95</sub>
                        </p>
                     </c>
                     <c ca="center">
                        <p>
                           <it>O</it>
                           <sub>11</sub>
                        </p>
                     </c>
                     <c ca="center">
                        <p>
                           <it>O</it>
                           <sub>1+</sub>
                        </p>
                     </c>
                     <c ca="center">
                        <p>
                           <it>O</it>
                           <sub>+1</sub>
                        </p>
                     </c>
                     <c ca="center">
                        <p>FP (%)</p>
                     </c>
                     <c ca="center">
                        <p>TP (%)</p>
                     </c>
                     <c ca="center">
                        <p>FN (%)</p>
                     </c>
                     <c ca="center">
                        <p>TN (%)</p>
                     </c>
                     <c ca="center">
                        <p>Global error</p>
                     </c>
                  </r>
                  <r>
                     <c cspan="13">
                        <hr/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>Independence case: <it>n </it>= 3000, common = 0, DE1 = 1000, DE2 = 800</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Independence: signal to noise</p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c ca="center">
                        <p>0.55</p>
                     </c>
                     <c ca="center">
                        <p>1*</p>
                     </c>
                     <c ca="center">
                        <p>0.98-1.02</p>
                     </c>
                     <c ca="center">
                        <p>0<sup>&#8224;</sup></p>
                     </c>
                     <c ca="center">
                        <p>0<sup>&#8224;</sup></p>
                     </c>
                     <c ca="center">
                        <p>0<sup>&#8224;</sup></p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                     <c ca="center">
                        <p>3,000 (100.0)</p>
                     </c>
                     <c ca="center">
                        <p>0</p>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>ratio = 0.4<sup>&#8225;</sup></p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>A: <it>n </it>= 3000, common = 700, DE1 = 1000, DE2 = 800</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case A1: signal to noise ratio = 9.6<sup>&#8225;</sup></p>
                     </c>
                     <c ca="left">
                        <p>Max</p>
                     </c>
                     <c ca="center">
                        <p>0.01</p>
                     </c>
                     <c ca="center">
                        <p>2.60</p>
                     </c>
                     <c ca="center">
                        <p>2.50-2.72</p>
                     </c>
                     <c ca="center">
                        <p>619</p>
                     </c>
                     <c ca="center">
                        <p>975</p>
                     </c>
                     <c ca="center">
                        <p>730</p>
                     </c>
                     <c ca="center">
                        <p>4 (0.2)</p>
                     </c>
                     <c ca="center">
                        <p>615 (87.8)</p>
                     </c>
                     <c ca="center">
                        <p>85 (12.2)</p>
                     </c>
                     <c ca="center">
                        <p>2,296 (99.8)</p>
                     </c>
                     <c ca="center">
                        <p>89</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c ca="left">
                        <p>Double</p>
                     </c>
                     <c ca="center">
                        <p>0.06</p>
                     </c>
                     <c ca="center">
                        <p>2.04</p>
                     </c>
                     <c ca="center">
                        <p>1.97-2.19</p>
                     </c>
                     <c ca="center">
                        <p>676</p>
                     </c>
                     <c ca="center">
                        <p>1,095</p>
                     </c>
                     <c ca="center">
                        <p>877</p>
                     </c>
                     <c ca="center">
                        <p>29 (1.3)</p>
                     </c>
                     <c ca="center">
                        <p>647 (92.4)</p>
                     </c>
                     <c ca="center">
                        <p>53 (7.6)</p>
                     </c>
                     <c ca="center">
                        <p>2,271 (98.7)</p>
                     </c>
                     <c ca="center">
                        <p>82</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c ca="center">
                        <p><it>Min</it><sup>&#167; </sup>= <it>81</it></p>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case A2: signal to noise ratio = 1.6<sup>&#8225;</sup></p>
                     </c>
                     <c ca="left">
                        <p>Max</p>
                     </c>
                     <c ca="center">
                        <p>0.01</p>
                     </c>
                     <c ca="center">
                        <p>4.72</p>
                     </c>
                     <c ca="center">
                        <p>4.19-5.29</p>
                     </c>
                     <c ca="center">
                        <p>86</p>
                     </c>
                     <c ca="center">
                        <p>346</p>
                     </c>
                     <c ca="center">
                        <p>157</p>
                     </c>
                     <c ca="center">
                        <p>1 (0.0)</p>
                     </c>
                     <c ca="center">
                        <p>85 (12.1)</p>
                     </c>
                     <c ca="center">
                        <p>615 (87.9)</p>
                     </c>
                     <c ca="center">
                        <p>2,299 (100.0)</p>
                     </c>
                     <c ca="center">
                        <p>616</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c ca="left">
                        <p>Double</p>
                     </c>
                     <c ca="center">
                        <p>0.08</p>
                     </c>
                     <c ca="center">
                        <p>2.01</p>
                     </c>
                     <c ca="center">
                        <p>1.90-2.20</p>
                     </c>
                     <c ca="center">
                        <p>212</p>
                     </c>
                     <c ca="center">
                        <p>677</p>
                     </c>
                     <c ca="center">
                        <p>459</p>
                     </c>
                     <c ca="center">
                        <p>28 (1.2)</p>
                     </c>
                     <c ca="center">
                        <p>184 (26.3)</p>
                     </c>
                     <c ca="center">
                        <p>516 (73.7)</p>
                     </c>
                     <c ca="center">
                        <p>2,272 (98.8)</p>
                     </c>
                     <c ca="center">
                        <p>544</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c ca="center">
                        <p><it>Min</it><sup>&#167; </sup>= <it>535</it></p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>B: <it>n </it>= 3000, common = 200, DE1 = 700, DE2 = 500</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case B1: signal to noise ratio = 9.6<sup>&#8225;</sup></p>
                     </c>
                     <c ca="left">
                        <p>Max<sup>&#182;</sup></p>
                     </c>
                     <c ca="center">
                        <p>0.01</p>
                     </c>
                     <c ca="center">
                        <p>1.72</p>
                     </c>
                     <c ca="center">
                        <p>1.58-1.86</p>
                     </c>
                     <c ca="center">
                        <p>185</p>
                     </c>
                     <c ca="center">
                        <p>691</p>
                     </c>
                     <c ca="center">
                        <p>467</p>
                     </c>
                     <c ca="center">
                        <p>8 (0.3)</p>
                     </c>
                     <c ca="center">
                        <p>177 (88.5)</p>
                     </c>
                     <c ca="center">
                        <p>23 (11.5)</p>
                     </c>
                     <c ca="center">
                        <p>2,792 (99.7)</p>
                     </c>
                     <c ca="center">
                        <p>31</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c ca="center">
                        <p><it>Min</it><sup>&#167; </sup>= <it>31</it></p>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case B2: signal to noise ratio = 1.6<sup>&#8225;</sup></p>
                     </c>
                     <c ca="left">
                        <p>Max</p>
                     </c>
                     <c ca="center">
                        <p>0.01</p>
                     </c>
                     <c ca="center">
                        <p>2.98</p>
                     </c>
                     <c ca="center">
                        <p>2.38-3.71</p>
                     </c>
                     <c ca="center">
                        <p>36</p>
                     </c>
                     <c ca="center">
                        <p>250</p>
                     </c>
                     <c ca="center">
                        <p>145</p>
                     </c>
                     <c ca="center">
                        <p>3 (0.1)</p>
                     </c>
                     <c ca="center">
                        <p>33 (16.7)</p>
                     </c>
                     <c ca="center">
                        <p>167 (83.3)</p>
                     </c>
                     <c ca="center">
                        <p>2,797 (99.9)</p>
                     </c>
                     <c ca="center">
                        <p>170</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c ca="left">
                        <p>Double</p>
                     </c>
                     <c ca="center">
                        <p>0.03</p>
                     </c>
                     <c ca="center">
                        <p>2.03</p>
                     </c>
                     <c ca="center">
                        <p>1.67-2.40</p>
                     </c>
                     <c ca="center">
                        <p>57</p>
                     </c>
                     <c ca="center">
                        <p>355</p>
                     </c>
                     <c ca="center">
                        <p>236</p>
                     </c>
                     <c ca="center">
                        <p>11 (0.4)</p>
                     </c>
                     <c ca="center">
                        <p>46 (23.0)</p>
                     </c>
                     <c ca="center">
                        <p>154 (77.1)</p>
                     </c>
                     <c ca="center">
                        <p>2,789 (99.6)</p>
                     </c>
                     <c ca="center">
                        <p>165</p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c ca="center">
                        <p><it>Min</it><sup>&#167; </sup>= <it>165</it></p>
                     </c>
                  </r>
                  <r>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c ca="left">
                        <p>
                           <b>C: <it>n </it>= 3000, common = 100, DE1 = 500, DE2 = 400</b>
                        </p>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                     <c>
                        <p/>
                     </c>
                  </r>
                  <r>
                     <c indent="1" ca="left">
                        <p>Case C1: signal to noise ratio = 9.6<sup>&#8225;</sup></p>
                     </c>
                     <c ca="left">
                        <p>Max<sup>&#182;</sup></p>
                     </c>
                     <c ca="center">
                        <p>0.01</p>
                     </c>
                     <c ca="center">
                        <p>1.48</p>
                     </c>
                     <c ca="center">
                        <p>1.30-1.67</p>
                     </c>
                     <c ca="center">
                        <p>95</p>
                     </c>
                     <c ca="center">
                        <p>500</p>
                     </c>
                     <c ca="center">
                        <p>383</p>
                     </c>
                     <c ca="center">
                        <p>7 (0.2)</p>
                     </c>
                     <c ca="center">
                        <p>88 (88.4)</p>
                     </c>
                     <c ca="center">
                        <p>12 (11.6)</p>
                     </c>
                     <c ca="center">
                        <p>2,893 (99.8)</p>
                     </c>
                     <c ca="center">
                    